Clock Detection Technique

             Clock detection technique

: Think about the clock before solving the question. The whole clock is like a circle. Then a circle is equal to 4 equal angle, ie 4 right angle or 360 ° Now imagine that the total number is 12. Then there will be an angle for every hour (360 ° ÷ 12) = 30 °. When extracting the value of the angle, remember that no one will be more than 180 ° or the difference is greater than 6. Now let's have some questions. Question 1: How many degrees in the clock when the angle between four o'clock, the hour's thorn and the minute thorns? Answer: 120 ° . Explanation: When it is four o'clock, the thorns will be at 4am and the thorns will be at 12 in the middle. As a result, the difference between the two cuts will be 4. I have already found out that the angle value for every hour is 30 °, so the angle value for 4 would be (30 ° x 4) = 120 ° . Question 2: How many degrees when the clock is at eight o'clock in the clock, the thorn and the thorn in the minute? Answer: 120 ° . Explanation: When the clock turns eight o'clock, the thorns will be at 8 o'clock and the thorns will be at 12 o'clock. As a result, the difference between the two cuts will be 4. Somebody can say 12 to 8 times the distance between 8 and 8, but it can not be done because the angle will be greater than 180 °, before the angle value can not be more than 180 °, so the difference will never be greater than 6. So the gap between 8 to 12 will be 4. I have already found out that the angle value for every hour is 30 °, so the angle value for 4 would be (30 ° x 4) = 120 ° . Question 3: When the clock is about eleven o'clock in the clock, how many degrees of angle between the thorns and minute thorns? Answer: 165 ° . Explanation: When the needle is eleven o'clock, the thorns will be between 11 and 12 midway, 11.5 and the minus one at 6. As a result, the difference between the two cuts will be 5.5. Others may think that the distance can be 6.5 and. Yes may be, but in this case there will never be more than 6, so from which the interval between the six is ​​equal to 6. I have already found that the angle value for 30 hours is equal to angle for every hour (30 ° × 5.5) = 165 °. If you remember just 1, then within 15 - 20 seconds, you can answer the following digits of the distance between the clock, hour and minute of the cut. Technique: (11 × M - 6O × H) ÷ 2 here, M = minute H = hour For example, if the clock is 2 to 40 minutes, then the degree of cutting and minimizing the number of minutes produces no. Formula: (11 × M - 6O × H) ÷2, (Here the minutes and places of H in place of M is to be set) Solution: (11x4O-6O × 2) ÷2 = 160 (U) [Bidra: It exceeds ° (that is, more than 180 °), but if the value obtained is reduced by 360, then its value must be calculated]

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